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750-220x+12x^2=0
a = 12; b = -220; c = +750;
Δ = b2-4ac
Δ = -2202-4·12·750
Δ = 12400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12400}=\sqrt{400*31}=\sqrt{400}*\sqrt{31}=20\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-20\sqrt{31}}{2*12}=\frac{220-20\sqrt{31}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+20\sqrt{31}}{2*12}=\frac{220+20\sqrt{31}}{24} $
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